How many triangles can be formed by joining 15 points when 7 of them are on the same straight line?

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To form a triangle we need 3 non-collinear points.

Take the 7 points lying on one line be group A and the remaining 8 points lying on another parallel line be group B.

We have the following possibilities

Group A
7 points
Group B
8 points
Combination
[i] 2 1 7C2 × 8C1
[ii] 1 2 7C1 × 8C2

∴ Required number of ways of forming the triangle

= [7C2 × 8C1] + [7C1 × 8C2]

= `[7!]/[2![7 - 2]!] xx 8 + 7 xx [8!]/[2![8 - 2]!]`

= `[7!]/[2 xx 5!] xx 8 + 7 xx [8!]/[2! xx 6!]`

= `[7 xx 6 xx 5! xx 8]/[2! xx 5!] + [7 xx 8 xx 7 xx 6!]/[2! xx 6!]`

= `[7 xx 6 xx 8]/[2! xx 5!] + [7 xx 8 xx  xx 6!]/[2! xx 6!]`

= `[7 xx 6 xx8]/[2 xx 1] + [7 xx 8 xx 7]/[2 xx 1]`

= 7 × 6 × 4 + 7 × 4 × 7

= 168 + 196

= 364

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